用tableview写了一个简单的通讯录,话不多说,咱们慢慢构建。
首先,你需要一个tableview(这是肯定的。。代码就不贴了哈),接下来,你需要对数据源进行处理,按A-Z首字母分类。
UILocalizedIndexedCollation *indexedCollation = [UILocalizedIndexedCollation currentCollation];
[self.sectionHeaderArray addObjectsFromArray:[indexedCollation sectionTitles]]; NSMutableArray *sortarray = [[NSMutableArray alloc] init]; for (int i = 0; i < self.sectionHeaderArray.count; i++) { NSMutableArray *sectionArray = [[NSMutableArray alloc] init];
[sortarray addObject:sectionArray];
} for (NSString *str in self.dataArray) { NSString *fitst = [EaseChineseToPinyin pinyinFromChineseString:str]; NSInteger index = [indexedCollation sectionForObject:[fitst substringFromIndex:0] collationStringSelector:@selector(uppercaseString)];
[sortarray[index] addObject:str];
} //每个section内的数组排序 for (int i = 0; i < [sortarray count]; i++) { NSArray *array = [[sortarray objectAtIndex:i] sortedArrayUsingComparator:^NSComparisonResult(NSString *obj1, NSString *obj2) { NSString *firstLetter1 = [EaseChineseToPinyin pinyinFromChineseString:obj1];
firstLetter1 = [[firstLetter1 substringToIndex:1] uppercaseString]; NSString *firstLetter2 = [EaseChineseToPinyin pinyinFromChineseString:obj2];
firstLetter2 = [[firstLetter2 substringToIndex:1] uppercaseString]; return [firstLetter1 caseInsensitiveCompare:firstLetter2];
}];
[sortarray replaceObjectAtIndex:i withObject:[NSMutableArray arrayWithArray:array]];
} //去掉空的section for (NSInteger i = [sortarray count] - 1; i >= 0; i--) { NSArray *array = [sortarray objectAtIndex:i]; if ([array count] == 0) {
[sortarray removeObjectAtIndex:i];
[self.sectionHeaderArray removeObjectAtIndex:i];
}
}
[self.sortArray addObjectsFromArray:sortarray];
[self.tableView reloadData];
接下来,你要给tableview设置一个索引。
-(NSArray )sectionIndexTitlesForTableView:(UITableView )tableView{
return self.sectionHeaderArray;
}
文/小五么么哒(简书作者)
原文链接:http://www.jianshu.com/p/d158ff5bd7b0
原文链接:http://www.jianshu.com/p/d158ff5bd7b0
扫码二维码 获取免费视频学习资料
- 本文固定链接: http://phpxs.com/post/5007/
- 转载请注明:转载必须在正文中标注并保留原文链接
- 扫码: 扫上方二维码获取免费视频资料
查 看2022高级编程视频教程免费获取