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c#使用XSLT将xml文档转换为html文档
使用xslt可以将xml文档转成html,如下c#函数:
需要引用下面的命名空间:
using System.Xml; using System.Xml.Xsl;
方法实现:
public static string ConvertXML(XmlDocument InputXMLDocument, string XSLTFilePath , XsltArgumentList XSLTArgs) { System.IO.StringWriter sw = new System.IO.StringWriter(); XslCompiledTransform xslTrans = new XslCompiledTransform(); xslTrans.Load(XSLTFilePath); xslTrans.Transform(InputXMLDocument.CreateNavigator(), XSLTArgs, sw); return sw.ToString(); }
示例xml文件如下:
<?xml version="1.0" encoding="utf-8" ?> <sexystars> <category name="Bollywood"> <sexystar name="Antra mali" /> <sexystar name="Deepika Padukone" /> <sexystar name="Mandira Bedi" /> </category> <category name="Hollywood"> <sexystar name="Jennifer Lopez" /> <sexystar name="Jessica Alba" /> </category> </sexystars>
示例xslt文件如下:
<?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes"/> <xsl:template match="sexystars"> <div> <xsl:apply-templates select="category" /> </div> </xsl:template> <xsl:template match="category"> <h2> <xsl:value-of select="@name"/> </h2> <ul> <xsl:apply-templates select="sexystar" /> </ul> </xsl:template> <xsl:template match="sexystar"> <li> <xsl:value-of select="@name"/> </li> </xsl:template> </xsl:stylesheet>
调用的c#代码:
XmlDocument xDoc=new XmlDocument(); xDoc.Load(@"C:\sample.xml"); string returnhtml = ConvertXML(xDoc, @"C:\sample.xslt", new XsltArgumentList());
将输入如下html:
<div> <h2>Bollywood</h2> <ul> <li>Antra mali</li> <li>Deepika Padukone</li> <li>Mandira Bedi</li> </ul> <h2>Hollywood</h2> <ul> <li>Jennifer Lopez</li> <li>Jessica Alba</li> </ul> </div>