使用表函数切割字符串

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CREATE OR REPLACE TYPE table_userid is table of varchar2(100); 

create or replace function get_userid_tab(v_str in varchar2) return table_userid pipelined as 

v_new_str varchar2(4000); 

begin 

  if nvl(v_str,null) is not  null then 


    v_new_str:=v_str; 

    while 1=1 loop 

      if instr(v_new_str,',')=0 then 

        pipe row(to_number(v_new_str)); 

        exit; 

      else 

        pipe row(to_number(substr(v_new_str,1,instr(v_new_str,',')-1))); 

        v_new_str:=substr(v_new_str,instr(v_new_str,',')+1); 

      end if; 

    end loop; 

  end if; 

  return; 

end; 

测试: select * from table(get_userid_tab('16,17,18,19,20')); 

结果: 
16 
17 
18 
19 
20