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一个LinkedList的实现,非java util 的实现,没有用java util容器,纯实现过程,主要看算法。
/* * To change this template, choose Tools | Templates * and open the template in the editor. */ package linkedlisttest; /** * * @author Lindily */ public class LinkedList<E> { int size = 0; Node<E> head = new Node(null, null, null); public LinkedList() { head.next = head.previous = head; } public void add(E node) { //核心 循环双向链表 Node<E> newNode = new Node(head.previous, node, head); //新节点的prev指向头结点的prev 新节点的next指向头结点 newNode.previous.next = newNode; //调整,新节点的前一个的后一个 newNode.next.previous = newNode; //调整,新节点的后一个的前一个 size++; } public Node get(int index) { if (index < 0 || index >= size) { throw new IndexOutOfBoundsException("Index:" + index + ",size:" + size); } Node node = head; if (index < (size >> 1)) { //index转为二进制带符号向右移动一个bit,相当于index/2 for (int i = 0; i <= index; i++) { //head是哑元,i<=index当index=0时,返回head.next node = node.next; //对头结点进行迭代 } }else{ for(int i=size;i>index;i--){ node=node.previous; } } return node; } public int size() { return size; } public static void main(String[] args) { LinkedList list = new LinkedList(); list.add(1); list.add(2); list.add(3); for (int i = 0; i < list.size; i++) { System.out.println(list.get(i).node); } } } class Node<E> { E node; Node<E> next; Node<E> previous; public Node(Node<E> previous, E node, Node<E> next) { this.node = node; this.next = next; this.previous = previous; } }
/* * To change this template, choose Tools | Templates * and open the template in the editor. */ package linkedlisttest; /** * * @author Lindily */ public class SingleLinkedList<T> { int size = 0; Node<T> head, tail; public SingleLinkedList() { head = tail = null; } public void add(T node) { if (size == 0) { head = tail = new Node<T>(node, null); } else { tail.next = new Node<T>(node, null); tail = tail.next; } size++; } public Node<T> get(int index) { if (index < 0 || index >= size) { throw new IndexOutOfBoundsException("Index:" + index + ",size:" + size); } Node<T> node = head; for (int i = 0; i < index; i++) { //当index=0时,i不小于index(零不小于零),于是直接return头结点,与linkedList不同,head不是哑元 node = node.next; //对头结点进行迭代 } return node; } public int size(){ return size; } public static void main(String[] args){ SingleLinkedList list=new SingleLinkedList(); list.add(1); list.add(2); list.add(3); for(int i=0;i<list.size();i++){ System.out.println(list.get(i).node); } } } class Node<T> { T node; Node<T> next; public Node(T node, Node next) { this.node = node; this.next = next; } }