清华大佬耗费三个月吐血整理的几百G的资源,免费分享!....>>>
android计算地图上两点距离的算法
接口:
实现类:
接口:
package com.computedistance; public interface DistanceComputeInterface { double getDistance(double lat1, double lng1, double lat2, double lng2); double getShortDistance(double lat1, double lon1, double lat2, double lon2); double getLongDistance(double lat1, double lon1, double lat2, double lon2); double getDistanceBySpeed(double speed, double timeSpace); double getAccurancyDistance(double lat_a, double lng_a, double lat_b, double lng_b); }
实现类:
package com.computedistance.impl; import java.security.InvalidParameterException; import com.baidu.mapapi.utils.DistanceUtil; import com.baidu.platform.comapi.basestruct.GeoPoint; import com.computedistance.DistanceComputeInterface; public class DistanceComputeImpl implements DistanceComputeInterface{ private final static double DEF_PI = 3.14159265359; // PI private final static double DEF_2PI= 6.28318530712; // 2*PI private final static double DEF_PI180= 0.01745329252; // PI/180.0 private final static double DEF_R =6370693.5; // radius of earth private static DistanceComputeImpl instance = null; public synchronized static DistanceComputeImpl getInstance(){ if (instance == null) { instance = new DistanceComputeImpl(); } return instance; } private DistanceComputeImpl(){} @Override public double getDistance(double lat1, double lng1, double lat2, double lng2) { GeoPoint p1LL = new GeoPoint((int) (lat1*1e6), (int) (lng1*1e6)); GeoPoint p2LL = new GeoPoint((int) (lat2*1e6), (int) (lng2*1e6)); double distance = DistanceUtil.getDistance(p1LL, p2LL); return distance/1000; } @Override public double getShortDistance(double lat1, double lon1, double lat2,double lon2) { double ew1, ns1, ew2, ns2; double dx, dy, dew; double distance; // 角度转换为弧度 ew1 = lon1 * DEF_PI180; ns1 = lat1 * DEF_PI180; ew2 = lon2 * DEF_PI180; ns2 = lat2 * DEF_PI180; // 经度差 dew = ew1 - ew2; // 若跨东经和西经180 度,进行调整 if (dew > DEF_PI) dew = DEF_2PI - dew; else if (dew < -DEF_PI) dew = DEF_2PI + dew; dx = DEF_R * Math.cos(ns1) * dew; // 东西方向长度(在纬度圈上的投影长度) dy = DEF_R * (ns1 - ns2); // 南北方向长度(在经度圈上的投影长度) // 勾股定理求斜边长 distance = Math.sqrt(dx * dx + dy * dy); return distance/1000; } @Override public double getLongDistance(double lat1, double lon1, double lat2,double lon2) { double ew1, ns1, ew2, ns2; double distance; // 角度转换为弧度 ew1 = lon1 * DEF_PI180; ns1 = lat1 * DEF_PI180; ew2 = lon2 * DEF_PI180; ns2 = lat2 * DEF_PI180; // 求大圆劣弧与球心所夹的角(弧度) distance = Math.sin(ns1) * Math.sin(ns2) + Math.cos(ns1) * Math.cos(ns2) * Math.cos(ew1 - ew2); // 调整到[-1..1]范围内,避免溢出 if (distance > 1.0){ distance = 1.0; } else if (distance < -1.0){ distance = -1.0; } // 求大圆劣弧长度 distance = DEF_R * Math.acos(distance); return distance/1000; } @Override public double getDistanceBySpeed(double speed, double timeSpace) { if (speed < 0 || timeSpace <= 0) { throw new InvalidParameterException(); } return speed * timeSpace; } @Override public double getAccurancyDistance(double lat_a, double lng_a,double lat_b, double lng_b) { double pk = (double) (180 / 3.14169); double a1 = lat_a / pk; double a2 = lng_a / pk; double b1 = lat_b / pk; double b2 = lng_b / pk; double t1 = Math.cos(a1) * Math.cos(a2) * Math.cos(b1) * Math.cos(b2); double t2 = Math.cos(a1) * Math.sin(a2) * Math.cos(b1) * Math.sin(b2); double t3 = Math.sin(a1) * Math.sin(b1); double tt = Math.acos(t1 + t2 + t3); return 6366000 * tt / 1000; } }